NCERT Solutions Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.2 Q6

## NCERT Solutions Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.2 Q6

NCERT Solutions for Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.2 Q6

coordinate geometry NCERT Solutions for Class 10th Maths Chapter 7 Ex 7.2 Q6

RD sharma solutions for class 11: http://www.cbselabs.com/forums/rd-sharma-class-11-solutions.46/

NCERT Solutions for maths in Video https://www.youtube.com/user/cbsepapers/videos

### Formulas

#### 1. Distance

If *A* ( *x*_{1}, *y*_{1}) and *B*( *x*_{2}, *y*_{2},), then distance *d*, from *A* to *B* =

#### 2. Midpoint

#### 3. Gradient/Slope

#### 4. Equation of a line

*y* = *mx* + *c*

**y – y _{1} = m(x – x_{1})**

#### 5. Parallel lines

If two lines are parallel, then they have the same gradient.

#### 6. Perpendicular lines

If two lines are perpendicular, then the product of the gradients of the two lines is **-1.**

or: perpendicular gradient = **-1/m** where m is the gradient of the line perpendicular to it.

#### 7. Area of triangle

The area of the triangle formed by the three points (x_{1}, y_{1}), (x_{2}, y_{2}), (x_{3}, y_{3})

**8. Shoelace formula**

- go anti-clockwise direction
- must go back to first coordinate

#### 9. Circle

The equation of a circle whose center is (h,k) and radius is **a** is given by the equation

**(x – h) ^{2} + (y – k)^{2} = 0**

The equation of a circle whose centre is the origin and whose radius is **a** is given by the equation

**x ^{2} + y^{2} = a^{2}**

The general equation of a circle is

**x ^{2} + y^{2 }+ 2gx + 2fy + c = 0**

where the centre is (-g,-f) and radius is

The equation of a circle whose one diameter is the line segment joining the points

(x_{1}, y_{1}), (x_{2}, y_{2}) is given by

(x – x_{1})(x – x_{2}) + (y – y_{1})(y – y_{2}) = 0

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